Dec 29, 2011 · In jQuery the variable is assigned a copy of the jQuery function. This function is heavily overloaded and means half a dozen different things depending on what arguments it is …

Dec 13, 2013 · The cash sign is just an alias for the jQuery function. Starting the variable name with $ has no effect on that variable. It is customary though, especially in jQuery plugin …

Mar 29, 2022 · A '$' in a variable means nothing special to the interpreter, much like an underscore. From what I've seen, many people using jQuery (which is what your example …

The Stack Overflow page discusses troubleshooting and solutions for the "jQuery is not defined" error in JavaScript.

$("div.id_100 > select > option[value=" + value + "]").prop("selected",true); Where value is the value you wish to select by. If you need to removed any prior selected values, as would be the …

Aug 23, 2012 · Yup — what you’re describing is a jQuery plugin. To write a jQuery plugin, you create a function in JavaScript, and assign it to a property on the object jQuery.fn.

Sep 9, 2013 · Jquery.ajax does not encode POST data for you automatically the way that it does for GET data. Jquery expects your data to be pre-formated to append to the request body to …

Sep 12, 2009 · $input.disabled = true; or $input.disabled = "disabled"; Which is the standard way? And, conversely, how do you enable a disabled input?

Nov 23, 2012 · jQuery itself uses the .data() method to save information under the names 'events' and 'handle', and also reserves any data name starting with an underscore ('_') for internal …

Oct 7, 2008 · How do I toggle the visibility of an element using .hide(), .show(), or .toggle()? How do I test if an element is visible or hidden?